diff-equation

Question: The solution of the differential equation $(1+{{x}^{2}})(1+y)dy+(1+x)(1+{{y}^{2}})dx=0$ is

1) ${{\tan }^{-1}}x+\log (1+{{x}^{2}})+{{\tan }^{-1}}y+\log (1+{{y}^{2}})=c$

2) ${{\tan }^{-1}}x-\frac{1}{2}\log (1+{{x}^{2}})+{{\tan }^{-1}}y-\frac{1}{2}\log (1+{{y}^{2}})=c$

3) ${{\tan }^{-1}}x+\frac{1}{2}\log (1+{{x}^{2}})+{{\tan }^{-1}}y+\frac{1}{2}\log (1+{{y}^{2}})=c$

4) None of these

Solution:

Explanation: No Explanation

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