diff-equation

Question: The solution of the differential equation $(1+{{x}^{2}})\frac{dy}{dx}=x$ is



1) $y={{\tan }^{-1}}x+c$
2) $y=-{{\tan }^{-1}}x+c$
3) $y=\frac{1}{2}{{\log }_{e}}(1+{{x}^{2}})+c$
4) $y=-\frac{1}{2}{{\log }_{e}}(1+{{x}^{2}})+c$
Solution: Explanation: No Explanation
Variable separable type differential equations

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