diff-equation

Question: If ${{x}^{2}}+{{y}^{2}}=1$ then $\left( {y}'=\frac{dy}{dx},{y}''=\frac{{{d}^{2}}y}{d{{x}^{2}}} \right)$



1) $y{y}''-2{{({y}')}^{2}}+1=0$
2) $y{y}''+{{({y}')}^{2}}+1=0$
3) $y{y}''-{{({y}')}^{2}}-1=0$
4) $y{y}''+2{{({y}')}^{2}}+1=0$
Solution: Explanation: No Explanation
Formation of differential equations

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