indefinite-integration

Question: $\int_{{}}^{{}}{\frac{{{x}^{2}}+1}{{{x}^{4}}+1}dx=}$

1) $\frac{1}{\sqrt{2}}{{\tan }^{-1}}\left( \frac{{{x}^{2}}-1}{2x} \right)+c$

2) $\frac{1}{\sqrt{2}}{{\tan }^{-1}}\left( \frac{{{x}^{2}}-1}{\sqrt{2x}} \right)+c$

3) $\frac{1}{\sqrt{2}}{{\tan }^{-1}}\left( \frac{{{x}^{2}}-1}{2\sqrt{x}} \right)+c$

4) $\frac{1}{\sqrt{2}}{{\tan }^{-1}}\left( \frac{{{x}^{2}}-1}{\sqrt{2}x} \right)+c$

Solution:

Explanation: No Explanation

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