indefinite-integration

Question: $\int_{{}}^{{}}{\sqrt{x}{{e}^{\sqrt{x}}}\ dx=}$



1) $2\sqrt{x}-{{e}^{\sqrt{x}}}-4\sqrt{x}\ {{e}^{\sqrt{x}}}+c$
2) $(2x-4\sqrt{x}+4){{e}^{\sqrt{x}}}+c$
3) $(2x+4\sqrt{x}+4){{e}^{\sqrt{x}}}+c$
4) $(1-4\sqrt{x}){{e}^{\sqrt{x}}}+c$
Solution: Explanation: No Explanation
Integration by parts

Rate this question:

Average rating: (0 votes)

Previous Question Next Question