indefinite-integration

Question: If $\int{f(x)\,\,dx=g(x),}$ then $\int{{{f}^{-1}}(x)}\,\,dx$ is equal to

1) ${{g}^{-1}}(x)$

2) $x{{f}^{-1}}(x)-g({{f}^{-1}}(x))$

3) $x{{f}^{-1}}(x)-{{g}^{-1}}(x)$

4) ${{f}^{-1}}(x)$

Solution:

Explanation: No Explanation

Integration by substitution

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