indefinite-integration

Question: $\int_{{}}^{{}}{\frac{{{e}^{m{{\tan }^{-1}}x}}}{1+{{x}^{2}}}dx}$ equals to

1) ${{e}^{{{\tan }^{-1}}x}}$

2) $\frac{1}{m}{{e}^{{{\tan }^{-1}}x}}$

3) $\frac{1}{m}{{e}^{m{{\tan }^{-1}}x}}$

4) None of these

Solution:

Explanation: No Explanation

Integration by substitution

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