indefinite-integration

Question: The value of $\int_{{}}^{{}}{\frac{{{x}^{3}}}{\sqrt{1+{{x}^{4}}}}\ dx}$ is

1) ${{(1+{{x}^{4}})}^{\frac{1}{2}}}+c$

2) $-{{(1+{{x}^{4}})}^{\frac{1}{2}}}+c$

3) $\frac{1}{2}{{(1+{{x}^{4}})}^{\frac{1}{2}}}+c$

4) $-\frac{1}{2}{{(1+{{x}^{4}})}^{\frac{1}{2}}}+c$

Solution:

Explanation: No Explanation

Integration by substitution

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