indefinite-integration

Question: $\int_{{}}^{{}}{\frac{{{e}^{{{\tan }^{-1}}x}}}{1+{{x}^{2}}}dx=}$

1) $\log (1+{{x}^{2}})+c$

2) $\log {{e}^{{{\tan }^{-1}}x}}+c$

3) ${{e}^{{{\tan }^{-1}}x}}+c$

4) ${{\tan }^{-1}}{{e}^{{{\tan }^{-1}}x}}+c$

Solution:

Explanation: No Explanation

Integration by substitution

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