indefinite-integration

Question: $\int_{{}}^{{}}{\frac{3{{x}^{2}}}{{{x}^{6}}+1}dx=}$

1) $\log ({{x}^{6}}+1)+c$

2) ${{\tan }^{-1}}({{x}^{3}})+c$

3) $3{{\tan }^{-1}}({{x}^{3}})+c$

4) $3{{\tan }^{-1}}\left( \frac{{{x}^{3}}}{3} \right)+c$

Solution:

Explanation: No Explanation

Integration by substitution

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