$\int_{{}}^{{}}{\frac{\sin x\ dx}{{{a}^{2}}+{{b}^{2}}{{\cos }^{2}}x}}=$

Question

Accepted Answer

$\frac{1}{ab}{{\cot }^{-1}}\left( \frac{b\cos x}{a} \right)+c$

Answer

$\log ({{a}^{2}}+{{b}^{2}}{{\cos }^{2}}x)+c$

Answer

$\frac{1}{ab}{{	an }^{-1}}\left( \frac{a\cos x}{b} ight)+c$

Answer

$\frac{1}{ab}{{\cot }^{-1}}\left( \frac{a\cos x}{b} \right)+c$

indefinite-integration