indefinite-integration

Question: If $\int_{{}}^{{}}{(\sin 2x-\cos 2x)}\ dx=\frac{1}{\sqrt{2}}\sin (2x-a)+b$, then

1) $a=\frac{\pi }{4},\ b=0$

2) $a=-\frac{\pi }{4},\ b=0$

3) $a=\frac{5\pi }{4},\ b=$any constant

4) $a=-\frac{5\pi }{4},\ b=$any constant

Solution:

Explanation: No Explanation

Fundamental integration

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