differentiation

Question: The function $f(x)=|px-q|+r|x|,$ $x\in (-\infty ,\infty )$ where $p>0,q>0,r>0$ assumes its minimum value only at one point if



1) $p\ne q$
2) $q\ne r$
3) $r\ne p$
4) $p=q=r$
Solution: Explanation: No Explanation
Maxima and Minima

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