Categories > differentiation > Tangent and Normal > The equation of the tangent to the curve $x=2{{\cos }^{3}}\theta $ and $y=3{{\sin }^{3}}\theta $ at the point $\theta =\pi /4$ is

differentiation

Question: The equation of the tangent to the curve $x=2{{\cos }^{3}}\theta $ and $y=3{{\sin }^{3}}\theta $ at the point $\theta =\pi /4$ is


1) $2x+3y=3\sqrt{2}$
2) $2x-3y=3\sqrt{2}$
3) $3x+2y=3\sqrt{2}$
4) $3x-2y=3\sqrt{2}$
Solution: Explanation: No Explanation
Tangent and Normal

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