differentiation

Question: The points on the curve $y=12x-{{x}^{3}}$ at which the gradient is zero are



1) (0, 2), (2,16)
2) (0, – 2), (2, – 16)
3) (2, –16), (– 2, 16)
4) (2, 16), (– 2, – 16)
Solution: Explanation: No Explanation
Tangent and Normal

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