differentiation

Related Questions

• If $y = (1 + {x^2}){\tan ^{ - 1}}x - x,$then $\frac{{dy}}{{dx}} = $

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• The area of the triangle formed by the coordinate axes and a tangent to the curve $xy={{a}^{2}}$ at the point $({{x}_{1}},{{y}_{1}})$ on it is

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• If $y = {\sec ^{ - 1}}\left( {\frac{{\sqrt x + 1}}{{\sqrt x - 1}}} \right) + {\sin ^{ - 1}}\left( {\frac{{\sqrt x - 1}}{{\sqrt x + 1}}} \right)$, then $\frac{{dy}}{{dx}} = $

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• ${{x}^{x}}$ has a stationary point at

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• If $y = \sin \left( {\frac{{1 + {x^2}}}{{1 - {x^2}}}} \right)$, then $\frac{{dy}}{{dx}} = $

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