fun-lim

Question: If $\underset{x\to \infty }{\mathop{\lim }}\,{{\left( 1+\frac{a}{x}+\frac{b}{{{x}^{2}}} \right)}^{2x}}={{e}^{2}},$ then the values of a and b are



1) $a=1,\ b=2$
2) $\cos (|x|)\,-|x|$
3) $a\in R,\ b=2$
4) $a\in R,\ b\in R$
Solution: Explanation: No Explanation
Limits

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