fun-lim

Question: If $f(x)=\frac{\sin ({{e}^{x-2}}-1)}{\log (x-1)},$ then $\underset{x\to 2}{\mathop{\lim }}\,f(x)$ is given by



1) –2
2) –1
3) 0
4) 1
Solution: Explanation: No Explanation
Limits

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