fun-lim

Question: If $f(x)=\frac{2}{x-3},\ g(x)=\frac{x-3}{x+4}$ and $h(x)=-\frac{2(2x+1)}{{{x}^{2}}+x-12},$ then $\underset{x\to 3}{\mathop{\lim }}\,[f(x)+g(x)+h(x)]$ is



1) $-2$
2) $-1$
3) $-\frac{2}{7}$
4) 0
Solution: Explanation: No Explanation
Limits

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