fun-lim

Question: If $f(x) = \begin{cases} x,\text{when x is rational} \\ 0, \text{when x is irrational} \end{cases}$ and $g(x) = \begin{cases} 0,\text{when x is rational} \\ x, \text{when x is irrational} \end{cases}$ then $(f-g)$ is



1) One-one onto
2) One-one not onto
3) Not one-one but onto
4) Not one-one not onto
Solution: Explanation: No Explanation
Functions

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