fun-lim

Question: Let $f:(-1,1)\to B$, be a function defined by $f(x)={{\tan }^{-1}}\frac{2x}{1-{{x}^{2}}},$ then f is both one- one and onto when B is the interval



1) $\left[ -\frac{\pi }{2},\frac{\pi }{2} \right]$
2) $\left( -\frac{\pi }{2},\frac{\pi }{2} \right)$
3) $\left( 0,\frac{\pi }{2} \right)$
4) $\left[ 0,\frac{\pi }{2} \right)$
Solution: Explanation: No Explanation
Functions

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