fun-lim

Question: If $f(x)={{e}^{2x}}$ and $g(x)=\log \sqrt{x}$$(x>0)$, then $fog(x)$ is equal to



1) ${{e}^{2x}}$
2) $\log \sqrt{x}$
3) ${{e}^{2x}}\log \sqrt{x}$
4) x
Solution: Explanation: No Explanation
Functions

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