fun-lim

Question: Let $f(x)=\sin x+\cos x,\ g(x)={{x}^{2}}-1$. Thus $g(f(x))$ is invertible for $x\in $



1) $\left[ -\frac{\pi }{2},\ 0 \right]$
2) $\left[ -\frac{\pi }{2},\ \pi \right]$
3) $\left[ -\frac{\pi }{2},\ \frac{\pi }{4} \right]$
4) $\left[ 0,\ \frac{\pi }{2} \right]$
Solution: Explanation: No Explanation
Functions

Rate this question:

Average rating: (0 votes)

Previous Question Next Question