fun-lim

Question: Let the function f be defined by $f(x)=\frac{2x+1}{1-3x}$, then ${{f}^{-1}}(x)$ is



1) $\frac{x-1}{3x+2}$
2) $\frac{3x+2}{x-1}$
3) $\frac{x+1}{3x-2}$
4) $\frac{2x+1}{1-3x}$
Solution: Explanation: No Explanation
Functions

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