3-d

Question: A plane which passes through the point (3, 2, 0) and the line $\frac{x-3}{1}=\frac{y-6}{5}=\frac{z-4}{4}$is



1) $x-y+z=1$
2) $x+y+z=5$
3) $x+2y-z=0$
4) $2x-y+z=5$
Solution: Explanation: No Explanation
Line and plane

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