3-d

Question: The point where the line $\frac{x-1}{2}=\frac{y-2}{-3}=\frac{z+3}{4}$ meets the plane $2x+4y-z=1$, is



1) (3, –1, 1)
2) (3, 1, 1)
3) (1, 1, 3)
4) (1, 3, 1)
Solution: Explanation: No Explanation
Line and plane

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