3-d

Question: If the lines $\frac{x-1}{-3}=\frac{y-2}{2k}=\frac{z-3}{2}$, $\frac{x-1}{3k}=\frac{y-5}{1}=\frac{z-6}{-5}$ are at right angles, then $k =$



1) –10
2) $\frac{10}{7}$
3) $\frac{-10}{7}$
4) $\frac{-7}{10}$
Solution: Explanation: No Explanation
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