3-d

Question: The point of intersection of the lines $\frac{x-5}{3}=\frac{y-7}{-1}=\frac{z+2}{1},$ $\frac{x+3}{-36}=\frac{y-3}{2}=\frac{z-6}{4}$ is

1) $21,\,\frac{5}{3},\frac{10}{3}$

2) $(\,2,\,10,\,4)$

3) $(-3,\,3,\,6)$

4) $(5,\,7,\,-2)$

Solution:

Explanation: No Explanation

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