3-d

Question: The equation of the line passing through the points ( 3, 2, 4) and (4, 5, 2) is

1) $\frac{x+3}{1}=\frac{y+2}{3}=\frac{z+4}{-2}$

2) $\frac{x-3}{1}=\frac{y-2}{3}=\frac{z-4}{-2}$

3) $\frac{x+3}{7}=\frac{y+2}{7}=\frac{z+4}{6}$

4) $\frac{x-3}{7}=\frac{y-2}{7}=\frac{z-4}{6}$

Solution:

Explanation: No Explanation

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