3-d

Question: The symmetric equation of lines $3x+2y+z-5=0$ and $x+y-2z-3=0$, is

1) $\frac{x-1}{5}=\frac{y-4}{7}=\frac{z-0}{1}$

2) $\frac{x+1}{5}=\frac{y+4}{7}=\frac{z-0}{1}$

3) $\frac{x+1}{-5}=\frac{y-4}{7}=\frac{z-0}{1}$

4) $\frac{x-1}{-5}=\frac{y-4}{7}=\frac{z-0}{1}$

Solution:

Explanation: No Explanation

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