vectors-m

Question: The area of the parallelogram whose diagonals are $\mathbf{a}=3\,\mathbf{i}+\mathbf{j}-2\mathbf{k}$ and $\mathbf{b}=\mathbf{i}-3\,\mathbf{j}+4\,\mathbf{k}$ is



1) $10\sqrt{3}$
2) $5\sqrt{3}$
3) 8
4) 4
Solution: Explanation: No Explanation
Vector Product Cross Product of two vectors

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