Categories > vectors-m > Vector Product > The scalars l and m such that $l\mathbf{a}+m\mathbf{b}=\mathbf{c},$ where a, b and c are given vectors, are equal to

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Question: The scalars l and m such that $l\mathbf{a}+m\mathbf{b}=\mathbf{c},$ where a, b and c are given vectors, are equal to


1) $l=\frac{(\mathbf{c}\times \mathbf{b})\,.\,(\mathbf{a}\times \mathbf{b})}{{{(\mathbf{a}\times \mathbf{b})}^{2}}},\,\,m=\frac{(\mathbf{c}\times \mathbf{a})\,.\,(\mathbf{b}\times \mathbf{a})}{{{(\mathbf{b}\times \mathbf{a})}^{2}}}$
2) $l=\frac{(\mathbf{c}\times \mathbf{b})\,.\,(\mathbf{a}\times \mathbf{b})}{(\mathbf{a}\times \mathbf{b})},\,\,m=\frac{(\mathbf{c}\times \mathbf{a})\,.\,(\mathbf{b}\times \mathbf{a})}{(\mathbf{b}\times \mathbf{a})}$
3) $l=\frac{(\mathbf{c}\times \mathbf{b})\,\times \,(\mathbf{a}\times \mathbf{b})}{{{(\mathbf{a}\times \mathbf{b})}^{2}}},\,\,m=\frac{(\mathbf{c}\times \mathbf{a})\,\times \,(\mathbf{b}\times \mathbf{a})}{(\mathbf{b}\times \mathbf{a})}$
4) None of these
Solution: Explanation: No Explanation
Vector Product Cross Product of two vectors

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