vectors-m

Question: If $(x,\,\,y,\,\,z)\ne (0,\,\,0,\,\,0)$ and $(\mathbf{i}+\mathbf{j}+3\,\mathbf{k})\,x+(3\,\mathbf{i}-3\mathbf{j}+\mathbf{k})\,y$ $+(-4\mathbf{i}+5\mathbf{j})\,z=\lambda \,(x\mathbf{i}+y\mathbf{j}+z\mathbf{k}),$ then the value of $\lambda$ will be



1) – 2, 0
2) 0, – 2
3) – 1, 0
4) 0, – 1
Solution: Explanation: No Explanation
Modulus of vector Algebra of vectors

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