If the straight line $x\cos \alpha +y\sin \alpha =p$ be a tangent to the hyperbola $\frac{{{x}^{2}}}{{{a}^{2}}}-\frac{{{y}^{2}}}{{{b}^{2}}}=1$, then

Question

Accepted Answer

${{a}^{2}}{{\cos }^{2}}\alpha -{{b}^{2}}{{\sin }^{2}}\alpha ={{p}^{2}}$

Answer

${{a}^{2}}{{\cos }^{2}}\alpha +{{b}^{2}}{{\sin }^{2}}\alpha ={{p}^{2}}$

Answer

${{a}^{2}}{{\sin }^{2}}\alpha +{{b}^{2}}{{\cos }^{2}}\alpha ={{p}^{2}}$

Answer

${{a}^{2}}{{\sin }^{2}}\alpha -{{b}^{2}}{{\cos }^{2}}\alpha ={{p}^{2}}$

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