conic-section

Question: The equation of the tangent at the point $(a\sec \theta ,\ b\tan \theta )$ of the conic $\frac{{{x}^{2}}}{{{a}^{2}}}-\frac{{{y}^{2}}}{{{b}^{2}}}=1$, is

1) $x{{\sec }^{2}}\theta -y{{\tan }^{2}}\theta =1$

2) $\frac{x}{a}\sec \theta -\frac{y}{b}\tan \theta =1$

3) $\frac{x+a\sec \theta }{{{a}^{2}}}-\frac{y+b\tan \theta }{{{b}^{2}}}=1$

4) None of these

Solution:

Explanation: No Explanation

Hyperbola

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