conic-section

Question: The latus rectum of the hyperbola $9{{x}^{2}}-16{{y}^{2}}-18x-32y-151=0$ is



1) $\frac{9}{4}$
2) 9
3) $\frac{3}{2}$
4) $\frac{9}{2}$
Solution: Explanation: No Explanation
Hyperbola

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