conic-section

Question: The latus-rectum of the hyperbola $16{{x}^{2}}-9{{y}^{2}}=$ $144$, is

1) $\frac{16}{3}$

2) $\frac{32}{3}$

3) $\frac{8}{3}$

4) $\frac{4}{3}$

Solution:

Explanation: No Explanation

Hyperbola

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