conic-section

Question: If $(0,\ \pm 4)$ and $(0,\ \pm 2)$ be the foci and vertices of a hyperbola, then its equation is

1) $\frac{{{x}^{2}}}{4}-\frac{{{y}^{2}}}{12}=1$

2) $\frac{{{x}^{2}}}{12}-\frac{{{y}^{2}}}{4}=1$

3) $\frac{{{y}^{2}}}{4}-\frac{{{x}^{2}}}{12}=1$

4) $\frac{{{y}^{2}}}{12}-\frac{{{x}^{2}}}{4}=1$

Solution:

Explanation: No Explanation

Hyperbola

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