conic-section

Question: If the latus rectum of an hyperbola be 8 and eccentricity be $3/\sqrt{5}$, then the equation of the hyperbola is

1) $4{{x}^{2}}-5{{y}^{2}}=100$

2) $5{{x}^{2}}-4{{y}^{2}}=100$

3) $4{{x}^{2}}+5{{y}^{2}}=100$

4) $5{{x}^{2}}+4{{y}^{2}}=100$

Solution:

Explanation: No Explanation

Hyperbola

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