conic-section

Question: If the normal at the point $P(\theta )$ to the ellipse $\frac{{{x}^{2}}}{14}+\frac{{{y}^{2}}}{5}=1$ intersects it again at the point $Q(2\theta )$ , then $\cos \theta $ is equal to

1) $\frac{2}{3}$

2) $-\frac{2}{3}$

3) $\frac{3}{2}$

4) $-\frac{3}{2}$

Solution:

Explanation: No Explanation

Ellipse

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