conic-section

Question: Equation of the ellipse with eccentricity $\frac{1}{2}$ and foci at $(\pm 1,\ 0)$ is



1) $\frac{{{x}^{2}}}{3}+\frac{{{y}^{2}}}{4}=1$
2) $\frac{{{x}^{2}}}{4}+\frac{{{y}^{2}}}{3}=1$
3) $\frac{{{x}^{2}}}{3}+\frac{{{y}^{2}}}{4}=\frac{4}{3}$
4) None of these
Solution: Explanation: No Explanation
Ellipse

Rate this question:

Average rating: (0 votes)

Previous Question Next Question