conic-section

Question: The eccentricity of an ellipse is 2/3, latus rectum is 5 and centre is (0, 0). The equation of the ellipse is

1) $\frac{{{x}^{2}}}{81}+\frac{{{y}^{2}}}{45}=1$

2) $\frac{4{{x}^{2}}}{81}+\frac{4{{y}^{2}}}{45}=1$

3) $\frac{{{x}^{2}}}{9}+\frac{{{y}^{2}}}{5}=1$

4) $\frac{{{x}^{2}}}{{{a}^{2}}}+\frac{{{y}^{2}}}{{{b}^{2}}}=1$

Solution:

Explanation: No Explanation

Ellipse

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