conic-section

Question: The ordinates of the triangle inscribed in parabola ${{y}^{2}}=4ax$ are ${{y}_{1}},\ {{y}_{2}},\ {{y}_{3}}$ , then the area of triangle is



1) $\frac{1}{8a}({{y}_{1}}+{{y}_{2}})({{y}_{2}}+{{y}_{3}})({{y}_{3}}+{{y}_{1}})$
2) $\frac{1}{4a}({{y}_{1}}+{{y}_{2}})({{y}_{2}}+{{y}_{3}})({{y}_{3}}+{{y}_{1}})$
3) $\frac{1}{8a}({{y}_{1}}-{{y}_{2}})({{y}_{2}}-{{y}_{3}})({{y}_{3}}-{{y}_{1}})$
4) $\frac{1}{4a}({{y}_{1}}-{{y}_{2}})({{y}_{2}}-{{y}_{3}})({{y}_{3}}-{{y}_{1}})$
Solution: Explanation: No Explanation
Parabola

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