conic-section

Question: If the normal to${{y}^{2}}=12x$ at (3, 6) meets the parabola again in (27, –18) and the circle on the normal chord as diameter is



1) ${{x}^{2}}+{{y}^{2}}+30x+12y-27=0$
2) ${{x}^{2}}+{{y}^{2}}+30x+12y+27=0$
3) ${{x}^{2}}+{{y}^{2}}-30x-12y-27=0$
4) ${{x}^{2}}+{{y}^{2}}-30x+12y-27=0$
Solution: Explanation: No Explanation
Parabola

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