conic-section

Question: The equations of the normals at the ends of latus rectum of the parabola ${{y}^{2}}=4ax$ are given by

1) ${{x}^{2}}-{{y}^{2}}-6ax+9{{a}^{2}}=0$

2) ${{x}^{2}}-{{y}^{2}}-6ax-6ay+9{{a}^{2}}=0$

3) ${{x}^{2}}-{{y}^{2}}-6ay+9{{a}^{2}}=0$

4) None of these

Solution:

Explanation: No Explanation

Parabola

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