conic-section

Question: The point on the parabola ${{y}^{2}}=8x$ at which the normal is inclined at $60^o$ to the x-axis has the co-ordinates



1) $(6,\ -4\sqrt{3})$
2) $(6,\ 4\sqrt{3})$
3) $(-6,\ -4\sqrt{3})$
4) $(-6,\ 4\sqrt{3})$
Solution: Explanation: No Explanation
Parabola

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