atomic-structure

Question: For an electron if the uncertainty in velocity is $\Delta \nu $, the uncertainty in its position $(\Delta x)$ is given by



1) $\frac{{hm}}{{4\pi \Delta \nu }}$
2) $\frac{{4\pi }}{{hm\Delta \nu }}$
3) $\frac{h}{{4\pi m\Delta \nu }}$
4) $\frac{{4\pi \;m}}{{h\;.\;\Delta \nu }}$
Solution: Explanation: No Explanation
Uncertainty Principle

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