atomic-structure

Question: The uncertainty in momentum of an electron is $1 \times {10^{ - 5}}kg\,m/s$. The uncertainity in its position will be $(h = 6.63 \times {10^{ - 34}}Js)$

1) $5.28 \times {10^{ - 30}}m$

2) $5.25 \times {10^{ - 28}}m$

3) $1.05 \times {10^{ - 26}}m$

4) $2.715 \times {10^{ - 30}}m$

Solution:

Explanation: No Explanation

Uncertainty Principle

Rate this question:

★ ★ ★ ★ ★

Average rating: (0 votes)