Categories > atomic-structure > Uncertainty Principle > The uncertainty in momentum of an electron is $1 \times {10^{ - 5}}kg - m/s$. The uncertainty in its position will be ($h = 6.62 \times {10^{ - 34}}kg - {m^2}/s$)

atomic-structure

Question: The uncertainty in momentum of an electron is $1 \times {10^{ - 5}}kg - m/s$. The uncertainty in its position will be ($h = 6.62 \times {10^{ - 34}}kg - {m^2}/s$)


1) $1.05 \times {10^{ - 28}}m$
2) $1.05 \times {10^{ - 26}}m$
3) $5.27 \times {10^{ - 30}}m$
4) $5.25 \times {10^{ - 28}}m$
Solution: Explanation: No Explanation
Uncertainty Principle

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