circle

Question: If the centre of a circle which passing through the points of intersection of the circles ${{x}^{2}}+{{y}^{2}}-6x+2y+4=0$ and ${{x}^{2}}+{{y}^{2}}+2x-4y-6=0$ is on the line $y=x$ , then the equation of the circle is



1) $7{{x}^{2}}+7{{y}^{2}}-10x+10y-11=0$
2) $7{{x}^{2}}+7{{y}^{2}}+10x-10y-12=0$
3) $7{{x}^{2}}+7{{y}^{2}}-10x-10y-12=0$
4) $7{{x}^{2}}+7{{y}^{2}}-10x-12=0$
Solution: Explanation: No Explanation
System of circles

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